В задачах 11.1 - 11.30 построить семейство кривых y = f(x) для указанных значений параметра l и оси координат с указанием минимального и максимального значений функции по каждой из осей.
11.1
0 £ j £ 360°; l = 5, 7.5, 15
11.2
0 £ j £ 360°; l = 50,150, 250
11.3
-60 £ j £ 60°; l = 10, 18, 26
11.4
0 £ j £ 6p; l = 5, 10, 15
11.5
0 £ j £ 360°; l = 1, 2, 3
11.6
-80° £ j £ 80°; l = 2, 3, 4
11.7
0 £ j £ 360°; l = 3, 4, 6
11.8
0 £ j £ 360°; l =-0.5, 1.5, 3;
A=10; a =-2.5
11.9
0 £ j £ 2p; l =0.5, 1, 2
11.10
0 £ j £ 360°; l =4, 6, 8;
A=24
11.11
-0.95 £ t £ 1; l =1, 2, 3
11.12
0 £ x £ 1; l =1.46, 2.92, 5; a =0.8
11.13
0 £ x £ 5; l =-0.2, -0.5, -0.8
11.14
-1 £ x < 6; A = 50; a = ln2/2;
w = p /2; l =0, p/6, p /3
11.15
-4 £ x £ 4; a = 1.83; b = 0.362;
d = -0.14; l =-1, -0.1, 1
11.16
-1 £ x < 1; a = 8.5; b = 0.85;
l =-0.5, 0, 0.5
11.17
0 £ t £ 2p; l =0.5, 1, 1.5
11.18
-30 £ t £ 30; l =-10, -15, -20;
11.19
-2 £ t £ 2; l =0.5, 1, 1.5
11.20
0 £ j £ 360°; l =1, 3, 5
11.21
10° £ j £ 80°; l =10, 12.5, 15
11.22
-10 £ t £ 10; l =3, 5, 7.5
11.23
0 £ j £ 2p; l =2.5, 5, 10
11.24
S0 = 0.03; b = 0.02; 0 £ x £ 20;
l =1, 3, 8
11.25
-10 £ x £ 10; l =1, 3, 5
11.26
0 £ t £ 4p; l =5, 7.5, 10
11.27
0.1 £ x £ 1.5; l =0.5, 1, 2
11.28
0 £ t £ 2p; l =2, 5, 7
11.29
-0.5 £ t £ 0.5; l =0.2, 0.5, 1
11.30
0 £ t £ 2p; l =5, 10, 15
